JEE Main 2019MathematicsApplication of DerivativesEasyMCQ

JEE Main 2019 — Application of Derivatives Question with Solution

JEE Main 2019 (09 Jan Shift 1)

Question

If θ denotes the acute angle between the curves, y=10-x2 and y=2+x2 at a point of their intersection, then tan⁡θ is equal to:

Choose an option

Show full solutionCorrect option: D
Correct answer
D815

Step-by-step explanation

Intersection points of given curves are ±2, 6, for 1st curve dydx=-2x

∴m1=4 or -4

For 2nd curve, dydx=2x

∴m2=-4 or 4

∴ |tanθ|=4--41+4-4 or -4-41+-44

=815 (In both cases)

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About this question

This is a previous-year question from JEE Main 2019, covering the Application of Derivatives chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.