JEE Main 2020ChemistrySurface ChemistryMediumNumerical

JEE Main 2020 — Surface Chemistry Question with Solution

JEE Main 2020 (02 Sep Shift 1)

Question

The mass of gas adsorbed, x, per unit mass of adsorbate, m, was measured at various pressures, p. A graph between log xm and log p gives a straight line with slope equal to 2 and the intercept equal to 0.4771. The value of xm at a pressure of 4 atm is :

(Given log 3=0.4771)

Enter your answer

Show full solutionCorrect answer: 48
Correct answer
48

Step-by-step explanation

xm=k(P)1n

logxm=logk+1nlogP

Slope =1n=2

so n=12

Intercept , logk = 0.477 So k = Antilog (0.477) = 3

so xm=k(P)1n

=3[4]2=48

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About this question

This is a previous-year question from JEE Main 2020, covering the Surface Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.