JEE Main 2008 — Structure Of Atom Question with Solution
From: AIEEE 2008
Question
The ionization enthalpy of hydrogen atom is 1.312 × 106 J mol−1. The energy required to excite the
electron in the atom from n = 1 to n = 2 is
Choose an option
Show full solutionCorrect option: D
Correct answer
D9.84 × 105 J mol−1
Step-by-step explanation
Note :
1 eV/atom = 96.485 103 J/mol
13.6 eV/atom = 13.6 96.485 103 J/mol = 1.312 × 106 J mol−1
Energy required to excite the electron from n1 to n2 is
= 1.312 × 106 × 1
= 1.312 × × 106
= 9.84 × 105 J mol−1
1 eV/atom = 96.485 103 J/mol
13.6 eV/atom = 13.6 96.485 103 J/mol = 1.312 × 106 J mol−1
Energy required to excite the electron from n1 to n2 is
= 1.312 × 106 × 1
= 1.312 × × 106
= 9.84 × 105 J mol−1
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This is a previous-year question from JEE Main 2008, covering the Structure Of Atom chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.