JEE Main 2019 — Structure Of Atom Question with Solution
From: JEE Main 2019 (Online) 10th January Evening Slot
Question
The ground state energy of hydrogen atom is – 13.6 eV. The energy of second excited state of He+ ion in eV is :
Choose an option
Show full solutionCorrect option: A
Correct answer
A 6.04
Step-by-step explanation
(E)nth = (EGND)H .
E3rd (He+) = (13.6eV) . = 6.04 eV
E3rd (He+) = (13.6eV) . = 6.04 eV
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This is a previous-year question from JEE Main 2019, covering the Structure Of Atom chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.