JEE Main 2013ChemistryStructure of AtomMediumMCQ

JEE Main 2013 — Structure of Atom Question with Solution

JEE Main 2013 (07 Apr)

Question

Energy of an electron is given by  E=-2.178×10-18Z2n2 J. Wavelength of light required to excite an electron in a hydrogen atom from level n=1 to n=2 will be :
h=6.62×10-34 Js and c=3.0×108 ms-1

Choose an option

Show full solutionCorrect option: C
Correct answer
C 1.214 × 1 0 - 7 m

Step-by-step explanation

E1=−2.178×10−18×11=−2.178×10−18J

=2.178×10−181.6×10−19=13.6 eV

E2=−2.178×10−8(2)2=−2.178×10−184=0.5448×10−18J

=−3.4 eV

ΔE=E2-E1=-3.4--13.6=10.2 eV

λ in Å=1240010.2≈1214 Å=1214×10−10m=1.214×10−7m    { ∴ 1 Å=10 −10 m }

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About this question

This is a previous-year question from JEE Main 2013, covering the Structure of Atom chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.