JEE Main 2017 — Structure Of Atom Question with Solution
From: JEE Main 2017 (Online) 9th April Morning Slot
Question
The electron in the hydrogen atom undergoes transition from higher orbitals
to orbital of radius 211.6 pm. This transition is associated with :
Choose an option
Show full solutionCorrect option: B
Correct answer
BBalmer series
Step-by-step explanation
Here electron is coming to the orbital of radius 211.6 pm. Now we have to find which series have radius of orbital 211.6 pm.
We know,
Radius, r =
Given, r = 211.6 pm = 211.6 10-12 m
and Z = 1 for hydrogen atom
211.6 10-12 = 10-10
n = 2
As n = 2 so the series is Balmer Series.
We know,
Radius, r =
Given, r = 211.6 pm = 211.6 10-12 m
and Z = 1 for hydrogen atom
211.6 10-12 = 10-10
n = 2
As n = 2 so the series is Balmer Series.
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Structure Of Atom chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2017, covering the Structure Of Atom chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.