JEE Main 2023 — Structure Of Atom Question with Solution

The orbital angular momentum (L) of an electron can be determined using the formula:

$$L=\sqrt{l(l+1)}\frac{h}{2\pi }$$

Where $$l$$ is the azimuthal quantum number (orbital angular momentum quantum number) and $$h$$ is the Planck's constant.

For a 3s orbital, the principal quantum number (n) is 3 and the azimuthal quantum number (l) is 0, as s orbitals have l=0. Now, let's calculate the orbital angular momentum:

$$L=\sqrt{0(0+1)}\frac{h}{2\pi }=0$$

Thus, the orbital angular momentum of an electron in a 3s orbital is 0. So, the value of $$x$$ is 0.