JEE Main 2016 — Some Basic Concepts Of Chemistry Question with Solution
From: JEE Main 2016 (Online) 9th April Morning Slot
Question
The amount of arsenic pentasulphide that can be obtained when 35.5 g arsenic acid istreated with excess H2S in the presence of conc. HCl ( assuming 100% conversion) is :
Choose an option
Show full solutionCorrect option: C
Correct answer
C0.125 mol
Step-by-step explanation
2H3 As O4 + 5H2S As2S5 + 8H2O
35.5 g of H3AsO4 = = 0.25 moles
Let, As2S5 produced = n moles.
n = 0.125 mol.
35.5 g of H3AsO4 = = 0.25 moles
Let, As2S5 produced = n moles.
n = 0.125 mol.
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