JEE Main 2019 — Some Basic Concepts Of Chemistry Question with Solution
From: JEE Main 2019 (Online) 12th April Morning Slot
Question
The mole fraction of a solvent in aqueous solution of a solute is 0.8. The molality (in mol kg–1
) of the
aqueous solution is :
Choose an option
Show full solutionCorrect option: C
Correct answer
C13.88
Step-by-step explanation
We know,
molality(m) =
Here solvent is H2O
xsolvent = 0.8
xsolute = 0.2
Molality = = 13.88
molality(m) =
Here solvent is H2O
xsolvent = 0.8
xsolute = 0.2
Molality = = 13.88
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