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JEE Main 2025Some Basic Concepts Of Chemistry Question with Solution

From: JEE Main 2025 (Online) 3rd April Morning Shift

Question

0.5 g of an organic compound on combustion gave 1.46 g of and 0.9 g of . The percentage of carbon in the compound is _______________. (Nearest integer)

[Given : Molar mass (in ]

Enter your answer

Show full solutionCorrect answer: 79.63
Correct answer
79.63

Step-by-step explanation

To determine the percentage of carbon in the organic compound, follow these steps:

Calculate Moles of CO₂:

Given: 1.46 g of CO₂ is produced.

Molar mass of CO₂ = 44 g/mol.

Moles of CO₂ = .

Determine Moles of Carbon Atoms:

Each molecule of CO₂ contains one atom of carbon.

Thus, moles of carbon = moles of CO₂.

Calculate Mass of Carbon:

Molar mass of carbon (C) = 12 g/mol.

Mass of carbon = Moles of carbon × 12 g/mol.

Mass of carbon = .

Calculate Percentage of Carbon:

Total mass of the organic compound = 0.5 g.

Percentage of carbon = .

Hence, Percentage of carbon = .

Percentage of carbon = 79.63%.

Therefore, the percentage of carbon in the compound is approximately 80%.

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About this question

This is a previous-year question from JEE Main 2025, covering the Some Basic Concepts Of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.