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JEE Main 2017 — Some Basic Concepts of Chemistry Question with Solution

JEE Main 2017 (02 Apr)

Question

1 gram of a carbonate M2CO3 on treatment with excess HCl produces 0.01186 moles of CO2 . The molar mass of M2CO3 in  gmol-1 is:

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Show full solutionCorrect option: A
Correct answer
A84.3

Step-by-step explanation

M2CO3+2HCl→2MCl+H2O+CO2

From reaction,

Moles of M2CO3=Moles of CO2

Weight of M2CO3Molar Mass of M2CO3 =Weight of CO2Molar mass of CO2

1Molar Mass of M2CO3 =0.01186 ×4444

 1Molar Mass of M2CO3=0.01186

Molar Mass  =10.01186=84.3 g/mol

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About this question

This is a previous-year question from JEE Main 2017, covering the Some Basic Concepts of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.