JEE Main 2020ChemistrySome Basic Concepts of ChemistryMediumNumerical

JEE Main 2020 — Some Basic Concepts of Chemistry Question with Solution

JEE Main 2020 (04 Sep Shift 2)

Question

A 100 mL solution was made by adding 1.43 g of Na2CO3.xH2O. The normality of the solution is 0.1 N. The value of x is _______

(The atomic mass of Na is 23g/mol)

Enter your answer

Show full solutionCorrect answer: 10
Correct answer
10

Step-by-step explanation

Equivalent of solute =0.1×0.1

Mole of solute Na2CO3,xH2O=[0.1×0.1]12

Mass of Na2CO3.xH2O=[0.1×0.1]12×[106+18x]=1.43

⇒     [106+18x=286

18 x=180

x=10 

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Some Basic Concepts of Chemistry chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2020, covering the Some Basic Concepts of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.