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JEE Main 2017 — Some Basic Concepts of Chemistry Question with Solution

JEE Main 2017 (08 Apr Online)

Question

Excess of NaOH (aq) was added to 100 mL of FeCl3 aq resulting into 2.14 g of FeOH3. The molarity of FeCl3aq is:

(Given the molar mass of Fe=56 g mol-1 and molar mass of Cl=35.5 g mol-1)

Choose an option

Show full solutionCorrect option: B
Correct answer
B0.2 M

Step-by-step explanation

Moles of FeOH3 =2.14107=2×10-2mol

Moles FeCl3=100 ml × 10−3 × M

According to stoichiometry, mole of FeCl3=Mole of Fe(OH)3

100 × 10−3 ×M=2 × 10−2

M=2×10-2100×1000=0.2 M

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About this question

This is a previous-year question from JEE Main 2017, covering the Some Basic Concepts of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.