JEE Main 2024ChemistrySome Basic Concepts of ChemistryHardNumerical

JEE Main 2024 — Some Basic Concepts of Chemistry Question with Solution

JEE Main 2024 (27 Jan Shift 2)

Question

Volume of 3M NaOH (formula weight 40 g mol-1 ) which can be prepared from 84 g of NaOH is ____×10-1dm3.

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Show full solutionCorrect answer: 7
Correct answer
7

Step-by-step explanation

Number of moles = Mass / Molar mass​

Molar mass of NaOH=40 g/mol

By Using  the definition of molarity to find the volume of the solution:

Molarity= Number of moles of soluteVolume of solution (in liters)

M=nNaOHVsol( in L)⇒3=(84/40)V⇒V=0.7 L=7×10-1 L

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About this question

This is a previous-year question from JEE Main 2024, covering the Some Basic Concepts of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.