JEE Main 2023ChemistrySome Basic Concepts of ChemistryEasyNumerical

JEE Main 2023Some Basic Concepts of Chemistry Question with Solution

JEE Main 2023 (11 Apr Shift 2)

Question

The volume of hydrogen liberated at STP by treating 2.4 g of magnesium with excess of hydrochloric acid is ......×10-2 L. Given Molar volume of gas is 22.4 L at STP. Molar mass of magnesium is 24 g mol-1
 

Enter your answer

Show full solutionCorrect answer: 224
Correct answer
224

Step-by-step explanation

The stoichiometric equation of the reaction between magnesium and hydrogen chloride can be written as follows,

One mole magnesium can liberate one mole of hydrogen gas according to the following equation.

 Mg2.4 g=0.1 mole+2HClMgCl2+H20.1 mole
Volume of 1 mole H2 at =22.4 L 
 0.1 mole H2 at STP will occupy =2.24 L

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Some Basic Concepts of Chemistry chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2023, covering the Some Basic Concepts of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.