JEE Main 2019ChemistrySome Basic Concepts of ChemistryMediumMCQ

JEE Main 2019 — Some Basic Concepts of Chemistry Question with Solution

JEE Main 2019 (12 Jan Shift 2)

Question

8 g of NaOH is dissolved in 18g of H2O. Mole fraction of NaOH in solution and molality (in  mol kg-1) of the solution respectively are:

Choose an option

Show full solutionCorrect option: A
Correct answer
A0.167,11.11

Step-by-step explanation

n1=840=0.2
n2=1818=1;
nt=n1+n2=0.2+1=1.2
Mole fraction of NaOH=n1nt=0.21.2=0.167
Molality =840×100018=11.11

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About this question

This is a previous-year question from JEE Main 2019, covering the Some Basic Concepts of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.