JEE Main 2019 — Solutions Question with Solution
From: JEE Main 2019 (Online) 9th April Evening Slot
Question
Molal depression constant for a solvent is
4.0 kg mol–1. The depression in the freezing
point of the solvent for 0.03 mol kg–1 solution
of K2SO4 is :
(Assume complete dissociation of the electrolyte)
(Assume complete dissociation of the electrolyte)
Choose an option
Show full solutionCorrect option: C
Correct answer
C0.36 K
Step-by-step explanation
K2SO4 2K+ + SO42-
Van’t Hoff Factor (i) = 3
Tf = ikfm
= 3 4 0.03 = 0.36 K
Van’t Hoff Factor (i) = 3
Tf = ikfm
= 3 4 0.03 = 0.36 K
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Solutions chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2019, covering the Solutions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.