JEE Main 2008 — Solutions Question with Solution
From: AIEEE 2008
Question
At 80oC, the vapour pressure of pure liquid ‘A’ is 520 mm Hg and that of pure liquid ‘B’ is 1000 mm Hg. If a mixture solution of ‘A’ and ‘B’ boils at 80oC and 1 atm pressure, the amount of ‘A’ in the mixture is (1 atm = 760 mm Hg)
Choose an option
Show full solutionCorrect option: D
Correct answer
D50 mol percent
Step-by-step explanation
At atmospheric pressure the boiling point of mixture is
At boiling point the vapour pressure of mixture,
atmosphere
Using the relation,
we get
or
or
or
or mol. percent
i.e., The correct answer is
At boiling point the vapour pressure of mixture,
atmosphere
Using the relation,
we get
or
or
or
or mol. percent
i.e., The correct answer is
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This is a previous-year question from JEE Main 2008, covering the Solutions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.