JEE Main 2016ChemistrySolutionsAbnormal Colligative Property And Vant Hoff FactoreasyMCQ

JEE Main 2016 — Solutions Question with Solution

From: JEE Main 2016 (Online) 10th April Morning Slot

Question

An aqueous solution of a salt MX2 at certain temperature has a van’t Hoff factor of 2. The degree of dissociation for this solution of the salt is :

Choose an option

Show full solutionCorrect option: B
Correct answer
B0.50

Step-by-step explanation

Let us assume that degree of dissociation is .

\matrix{ {M{X_2}} & { \to {M^{2 + }} + } & {2X + } \cr {(1 - \alpha )} & \alpha & {2\alpha } \cr }

Thus, after dissociation total number of moles formed (n) = 3.

Now, we know degree of dissociation is

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About this question

This is a previous-year question from JEE Main 2016, covering the Solutions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.