JEE Main 2019ChemistrySolutionsRelative Lowering Of Vapour Pressure And Roults LawmediumMCQ

JEE Main 2019Solutions Question with Solution

From: JEE Main 2019 (Online) 9th April Morning Slot

Question

Liquid 'M' and liquid 'N' form an ideal solution. The vapour pressures of pure liquids 'M' and 'N' are 450 and 700 mmHg, respectively, at the same temperature. Then correct statement is:
(xM = Mole fraction of 'M' in solution ;
xN = Mole fraction of 'N' in solution ;
yM = Mole fraction of 'M' in vapour phase ;
yN = Mole fraction of 'N' in vapour phase)

Choose an option

Show full solutionCorrect option: D
Correct answer
D

Step-by-step explanation

= 450 mmHg and = 700 mmHg

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About this question

This is a previous-year question from JEE Main 2019, covering the Solutions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.