JEE Main 2024 — Solutions Question with Solution

To calculate the osmotic pressure of the solution at the new temperature, we can use the formula:

$\pi =\text{CRT}$

Since the concentration $C$ and the gas constant $R$ remain constant, the ratio of the osmotic pressures at two different temperatures is given by:

$\frac{{\pi }_1}{{\pi }_2}=\frac{T_1}{T_2}$

Thus, we can express the osmotic pressure at the second temperature as:

${\pi }_2=\frac{{\pi }_1\cdot T_2}{T_1}$

Substituting the given values:

${\pi }_2=\frac{7\times 10^5\times 283}{273}$

After calculation, this simplifies to:

${\pi }_2=72.56\times 10^4{\text{Nm}}^{-2}$