JEE Main 2020 — Solutions Question with Solution
From: JEE Main 2020 (Online) 9th January Morning Slot
Question
How much amount of NaCl should be added
to 600 g of water ( = 1.00 g/mL) to decrease
the freezing point of water to – 0.2 °C ?
______.
(The freezing point depression constant for water = 2K kg mol–1)
(The freezing point depression constant for water = 2K kg mol–1)
Enter your answer
Show full solutionCorrect answer: 1.76
Correct answer
1.76
Step-by-step explanation
Tf = 0.2o C
Tf = ikf.m
i = 2 for NaCl
0.2 = 22
WNaCl = = 1.76 g
Tf = ikf.m
i = 2 for NaCl
0.2 = 22
WNaCl = = 1.76 g
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