JEE Main 2019 — Solutions Question with Solution
From: JEE Main 2019 (Online) 9th April Morning Slot
Question
The osmotic pressure of a dilute solution of an
ionic compound XY in water is four times that
of a solution of 0.01 M BaCl2 in water.
Assuming complete dissociation of the given
ionic compounds in water, the concentration of
XY (in mol L–1) in solution is :
Choose an option
Show full solutionCorrect option: B
Correct answer
B6 × 10–2
Step-by-step explanation
Given that, osmotic pressure of XY() in water is four times that
of a solution of 0.01 M BaCl2().
= 4
2 [XY] = 4 3 0.01
[XY] = 0.06 = 6 × 10–2 mol L–1
= 4
2 [XY] = 4 3 0.01
[XY] = 0.06 = 6 × 10–2 mol L–1
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