JEE Main 2020 — Solutions Question with Solution
From: JEE Main 2020 (Online) 7th January Morning Slot
Question
At 35oC, the vapour pressure of CS2
is 512 mm. Hg and that of acetone is 344 mm Hg. A solution
of CS2
in acetone has a total vapour pressure of 600 mm Hg. The false statement amongst the
following is :
Choose an option
Show full solutionCorrect option: B
Correct answer
Ba mixture of 100 ml. CS2 and 100 ml. acetone has a volume < 200 ml.
Step-by-step explanation
As the vapour pressure of mixture increases so the force of attraction of mixture is less than the individual component.
Since the vapour pressure of the solution is greater than individual vapour pressure of both pure components, the solution shows a positive deviation from Raoult’s law.
SolH 0
As SolH 0 then solution is endothermic.
and here Sol Volume 0. As Sol Volume 0 then a mixture of 100 ml. CS2 and 100 ml. acetone has a volume more than 200 ml. It happens because the distance between molecules increases due to force of attraction of mixture decreases.
Since the vapour pressure of the solution is greater than individual vapour pressure of both pure components, the solution shows a positive deviation from Raoult’s law.
SolH 0
As SolH 0 then solution is endothermic.
and here Sol Volume 0. As Sol Volume 0 then a mixture of 100 ml. CS2 and 100 ml. acetone has a volume more than 200 ml. It happens because the distance between molecules increases due to force of attraction of mixture decreases.
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Solutions chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2020, covering the Solutions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.