JEE Main 2019ChemistrySolid StateHardMCQ

JEE Main 2019Solid State Question with Solution

JEE Main 2019 (08 Apr Shift 1)

Question

Element B forms ccp structure and A occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is:

Choose an option

Show full solutionCorrect option: B
Correct answer
BAB2O4

Step-by-step explanation

For ccp structure:
Number of octahedral voids are =4
Number of tetrahedral voids are =8
ZB=4 (number of atoms present in ccp structure)
ZA=12×4=2
ZO=8
So formula is A2B4O8=AB2O4.

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About this question

This is a previous-year question from JEE Main 2019, covering the Solid State chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.