JEE Main 2023 — Salt Analysis Question with Solution

A confirmatory test for $P{b}^{2+}$ ions involves the formation of a specific compound that indicates the presence of lead ions in a solution.

Let's go through the options:

Option A: Lead chromate (${\mathrm{PbCrO}}_4$) forms a yellow precipitate, which is a confirmatory test for $P{b}^{2+}$ ions.

Option B: Lead iodide (${\mathrm{PbI}}_2$) forms a yellow precipitate, which is a confirmatory test for $P{b}^{2+}$ ions.

Option C: Lead sulfate (${\mathrm{PbSO}}_4$) forms a white precipitate, which is a confirmatory test for $P{b}^{2+}$ ions.

Option D: Lead nitrate ($\mathrm{Pb}(\mathrm{N}{\mathrm{O}}_3{)}_2$) is soluble in water and does not form a precipitate under normal conditions. Thus, its formation is not used as a confirmatory test for $P{b}^{2+}$ ions.

So, the correct answer is Option D: lead nitrate.