JEE Main 2019 — Redox Reactions Question with Solution
From: JEE Main 2019 (Online) 8th April Morning Slot
Question
In order to oxidise a mixture of one mole of each of FeC2O4, Fe2(C2O4)3, FeSO4 and Fe2(SO4)3 in
acidic medium, the number of moles of KMnO4 required is :
Choose an option
Show full solutionCorrect option: C
Correct answer
C2
Step-by-step explanation
Equivalent of KMnO4 = Eq of FeC2O4 + Eq of Fe2(C2O4)3 + FeSO4
moles of KMnO4 5 = 3 1 + 6 1 + 1 1
moles of KMnO4 = = 2
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This is a previous-year question from JEE Main 2019, covering the Redox Reactions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.