JEE Main 2022ChemistryRedox ReactionsEasyNumerical

JEE Main 2022 — Redox Reactions Question with Solution

JEE Main 2022 (27 Jul Shift 2)

Question

The normality of H2SO4 in the solution obtained on mixing 100 mL of 0.1M H2SO4 with 50 mL of 0.1M NaOH is____×10-1 N.

Enter your answer

Show full solutionCorrect answer: 1
Correct answer
1

Step-by-step explanation

No. of equivalents of H2SO4=M×V×n-factor = 100×0.1×2=20

No. of equivalents of NaOH=50×0.1=5

No. of equivalents of H2SO4 left =20-5=15

⇒150×x=15

x=110=0.1 N=1×10-1 N

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Redox Reactions chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2022, covering the Redox Reactions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.