JEE Main 2020ChemistryRedox ReactionsEasyNumerical

JEE Main 2020Redox Reactions Question with Solution

JEE Main 2020 (02 Sep Shift 2)

Question

The oxidation states of transition metal atoms in K2Cr2O7, KMnO4 and K2FeO4, respectively, are x,y and z . The sum of x, y and z is______

Enter your answer

Show full solutionCorrect answer: 19
Correct answer
19

Step-by-step explanation

Compound  Oxidation state of transition element.

Oxidation states of K =+1 and O=-2

(i) K2Cr2O7     x=+6
(ii) KMnO4          y=+7
(iii) K2FeO4        z=+6
so (x+y+z)=19

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Redox Reactions chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2020, covering the Redox Reactions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.