JEE Main 2023ChemistryRedox ReactionsMediumNumerical

JEE Main 2023 — Redox Reactions Question with Solution

JEE Main 2023 (13 Apr Shift 2)

Question

See the following chemical reaction:

Cr2O72-+XH++6Fe2+→YCr3++6Fe3++ZH2O

The sum of X, Y and Z is

Enter your answer

Show full solutionCorrect answer: 23
Correct answer
23

Step-by-step explanation

The given equation can be balanced using ion-electron method as shown below.

Fe2+→Fe3++e-         -oxidation Half reaction

6e-+14H++Cr2O72-→2Cr3++7H2O -Reduction Half reaction

The overall reaction is 

6Fe2++14H++Cr2O72-→6Fe3++2Cr3++7H2O

The values X=14,Y=2 and Z = 7

(X+ Y +Z)  = 14 + 2 +7

= 23

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About this question

This is a previous-year question from JEE Main 2023, covering the Redox Reactions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.