JEE Main 2021 — Redox Reactions Question with Solution
From: JEE Main 2021 (Online) 27th July Morning Shift
Question
The oxidation states of 'P' in H4P2O7, H4P2O5 and H4P2O6, respectively, are :
Choose an option
Show full solutionCorrect option: C
Correct answer
C5, 3 and 4
Step-by-step explanation
Oxidation state of P in H4P2O7, H4P2O5 and H4P2O6 is 5, 3 & 4 respectively
H4P2O7
2x + 4(+ 1) + 7 (2) = 0
x = + 5
2x + 4(+ 1) + 5 (2) = 0
x = + 3
2x + 4 (+ 1) + 6(2) = 0
x = +4
H4P2O7
2x + 4(+ 1) + 7 (2) = 0
x = + 5
2x + 4(+ 1) + 5 (2) = 0
x = + 3
2x + 4 (+ 1) + 6(2) = 0
x = +4
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Redox Reactions chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2021, covering the Redox Reactions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.