JEE Main 2024ChemistryPractical ChemistryMediumMCQ

JEE Main 2024Practical Chemistry Question with Solution

JEE Main 2024 (06 Apr Shift 2)

Question

During the detection of acidic radical present in a salt, a student gets a pale yellow precipitate soluble with difficulty in solution when sodium carbonate extract was first acidified with dil. and then solution was added. This indicates presence of :

Choose an option

Show full solutionCorrect option: A
Correct answer
A

Step-by-step explanation

$\begin{array}{ll} \mathrm{Ag}^{+}+\mathrm{I}^{-} \rightarrow \mathrm{AgI} & \text{Yellow ppt.} \\ \mathrm{Ag}^{+}+\mathrm{Cl}^{-} \rightarrow \mathrm{AgCl} & \text{White ppt} \\ \mathrm{Ag}^{+}+\mathrm{Br}^{-} \rightarrow \mathrm{AgBr} & \text{Pale yellow ppt} \end{array}$

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Practical Chemistry chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2024, covering the Practical Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.