JEE Main 2023ChemistryPolymersMediumMCQ

JEE Main 2023 — Polymers Question with Solution

JEE Main 2023 (11 Apr Shift 2)

Question

Given below are two statements:
Statement I: Ethane at 333 to 343 K and 6-7 atm pressure in the presence of AlEt3 and TiCl4 undergoes addition polymerization to give LDP.
Statement II: Caprolactam at 533-543 K in H2O through step growth polymerizes to give Nylon 6.

In the light of the above statements, choose the correct answer from the options given below:

Choose an option

Show full solutionCorrect option: A
Correct answer
AStatement I is false but Statement II is true

Step-by-step explanation

Low Density Polyethylene is obtained by the polymerisation of ethene under high pressure of 1000-2000 atm at 350-570 K in the presence of an initiator. High Density Polyethylene is obtained when polymerisation is done in the presence of Ziegler-Natta catalyst at 333-343K under 6-7 atm pressure. Nylon-6 is manufactured from the monomer called caprolactam. The monomer caprolactam is heated at 533-543Kin an inert atmosphere, it polymerises to give nylon-6.

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About this question

This is a previous-year question from JEE Main 2023, covering the Polymers chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.