JEE Main 2023 — Polymers Question with Solution
From: JEE Main 2023 (Online) 11th April Evening Shift
Question
Given below are two statements :
Statement I : Ethene at 333 to and - atm pressure in the presence of and undergoes addition polymerization to give LDP.
Statement II : Caprolactam at - in through step growth polymerizes to give Nylon 6.
In the light of the above statements, choose the correct answer from the options given below:
Choose an option
Show full solutionCorrect option: C
Step-by-step explanation
Statement I is false. Ethene (ethylene) under certain conditions (high pressure, high temperature) in the presence of catalysts does undergo addition polymerization, but it forms polyethylene, not LDP (Low-Density Polyethylene) specifically. The formation of low-density polyethylene (LDPE) vs high-density polyethylene (HDPE) depends on the specific conditions and catalysts used. The catalysts mentioned (AlEt3 and TiCl4) are associated with the production of HDPE through the Ziegler-Natta process, not LDPE.
Statement II is true. Caprolactam polymerizes to form Nylon 6 via a ring-opening polymerization mechanism, which is a type of step-growth polymerization. The process is often carried out at high temperatures, and water is a byproduct of the reaction, so the description in Statement II is accurate.
Therefore, Option C (Statement I is false but Statement II is true) is the correct answer.
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Polymers chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2023, covering the Polymers chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.