JEE Main 2019Chemistryp Block Elements (Group 15, 16, 17 & 18)EasyMCQ

JEE Main 2019 — p Block Elements (Group 15, 16, 17 & 18) Question with Solution

JEE Main 2019 (12 Jan Shift 1)

Question

Iodine reacts with concentrated HNO3 to yield Y along with other products. The oxidation state of iodine in Y , is:

Choose an option

Show full solutionCorrect option: B
Correct answer
B5

Step-by-step explanation

I2+10 HNO3→2 HIO3+10 NO2+4 H2O

Iodine gets oxidized to IO3- when it reacts with an oxidizing agent HNO3. The oxidation number of I in product will be

Oxidation:  I 2 −I O 3 −

-1=x+3×-2

-1=x-6

x=-1+6=+5

Reduction: concentrated HNO3 gives NO2.

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About this question

This is a previous-year question from JEE Main 2019, covering the p Block Elements (Group 15, 16, 17 & 18) chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.