JEE Main 2024 — p Block Elements (Group 15, 16, 17 & 18) Question with Solution

The total number of electrons that an atom either gains or loses in order to form a chemical bond with another atom is known as the Oxidation Number.

In ${\mathrm{H}}_2{\mathrm{SO}}_3$

 Let the oxidation number of S be x.

$$\begin{gathered} 2(+1) + \mathrm{x} + 3(-2) = 0 \\ \mathrm{x} = +4 \end{gathered}$$ 

Similarly the $+4$oxidation state of sulphur is shown by ${\mathrm{SOCl}}_2 \mathrm{and} {\mathrm{SF}}_4$.

$\begin{array}{|ccccccc|}\hline \text{ Compounds }& {\mathrm{SO}}_3& {\mathrm{H}}_2{\mathrm{SO}}_3& {\mathrm{SOCl}}_2& {\mathrm{SF}}_4& {\mathrm{BaSO}}_4& {\mathrm{H}}_2 {\mathrm{S}}_2{\mathrm{O}}_7\\ \text{ O.S.of Sulphur: }& +6& +4& +4& +4& +6& +6\\ \hline\end{array}$