JEE Main 2020Chemistryp Block Elements (Group 15, 16, 17 & 18)EasyNumerical

JEE Main 2020 — p Block Elements (Group 15, 16, 17 & 18) Question with Solution

JEE Main 2020 (03 Sep Shift 2)

Question

The volume (in mL) of 0.1 N NaOH required to neutralise10 mL of 0.1 N phosphinic acid is ____________.

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Show full solutionCorrect answer: 10
Correct answer
10

Step-by-step explanation

Phosphinic acid is hypo phosphorous acid H3PO2.

NaOH+H3PO2 → NaH2PO2+H2O

For neutrization

N1V1acid=N2V2base

0.1×10=0.1×VmLNaOH

VNaOH=10 mL

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About this question

This is a previous-year question from JEE Main 2020, covering the p Block Elements (Group 15, 16, 17 & 18) chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.