JEE Main 2020Chemistryp Block Elements (Group 15, 16, 17 & 18)EasyMCQ

JEE Main 2020 — p Block Elements (Group 15, 16, 17 & 18) Question with Solution

JEE Main 2020 (07 Jan Shift 2)

Question

In the following reactions, products A and B , respectively, are:
NaOH+Cl2→A+side products
hot and conc.


CaOH2+Cl2→B+side products
dry

Choose an option

Show full solutionCorrect option: A
Correct answer
ANaClO3 and CaOCl2

Step-by-step explanation

Here,

NaOH gives NaClO3 on reaction with chlorine gas.

CaOH2 gives CaOCl2 on reaction with chlorine gas.

6NaOH+3Cl2hot and conc→NaClO3A+5NaCl+3H2O2CaOH2dry+2Cl2→CaOCl2B+CaCl2+2H2O

CaOCl2 is known as bleaching powder.

 

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the p Block Elements (Group 15, 16, 17 & 18) chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2020, covering the p Block Elements (Group 15, 16, 17 & 18) chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.