JEE Main 2023Chemistryp Block Elements (Group 15, 16, 17 & 18)HardNumerical

JEE Main 2023 — p Block Elements (Group 15, 16, 17 & 18) Question with Solution

JEE Main 2023 (10 Apr Shift 2)

Question

The difference in the oxidation state of Xe between the oxidised product of Xe formed on complete hydrolysis of XeF4and XeF4 is

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Show full solutionCorrect answer: 2
Correct answer
2

Step-by-step explanation

Hydrolysis of XeF4 will give XeO3. This hydrolysis reaction is a redox reaction. This redox reaction is an example of disproportionation reaction.

6XeF4+12H2O→4Xe + 2XeO3+24HF+3O2

The oxidation states of Xenon in the reactant and product is 

XeO3:Xe(+6)

XeF4:Xe(+4)

Hence, the difference in oxidation state is 2.

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About this question

This is a previous-year question from JEE Main 2023, covering the p Block Elements (Group 15, 16, 17 & 18) chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.