JEE Main 2024 — p Block Elements (Group 13 & 14) Question with Solution

Statement I,

$$\begin{gathered} \mathrm{SnO}, \mathrm{PbO}, {\mathrm{SnO}}_2, {\mathrm{PbO}}_2 : \text{Amphoteric} \\ {\mathrm{CO}}_2, {\mathrm{SiO}}_2, {\mathrm{GeO}}_2, \mathrm{GeO} : \text{Acidic} \\ \mathrm{CO} :\text{ Neutral} \end{gathered}$$

According to Statement II,
Carbon does not have d-orbitals so can not form $\mathrm{p\pi }-\mathrm{d\pi }$ Bond with itself. Due to properties of catenation and $\mathrm{p\pi }-\mathrm{p\pi }$ bond formation, carbon is able to show allotropic forms. Allotropic forms of carbon can be crystalline and amorphous.
Diamond and graphite are two well-known crystalline forms of carbon. 

Hence option C is the answer.