JEE Main 2022Chemistryp Block Elements (Group 13 & 14)MediumMCQ

JEE Main 2022p Block Elements (Group 13 & 14) Question with Solution

JEE Main 2022 (24 Jun Shift 1)

Question

Identify the correct statement for B2H6 from those given below.

(A) In B2H6, all B-H bonds are equivalent.

(B) In B2H6, there are four 3-centre- 2-electron bonds.

(C) B2H6 is a Lewis acid.

(D) B2H6 can be synthesized from both BF3 and NaBH4.

(E) B2H6 is a planar molecule.

Choose the most appropriate answer from the options given below :

Choose an option

Show full solutionCorrect option: C
Correct answer
CC and D only

Step-by-step explanation

B2H6 have four 2c-2e bonds and two 3c-2e bonds. Bridging bonds have larger bond length than terminal bonds. Angle between terminal bonds is more than angle between bridging bonds if all 4 terminal bonds are in one plane then bridging bonds are in perpendicular plane.

3NaBH4+4BF3ether450 K3NaBF4+2B2H6

Therefore we can say that only statement (C) and (D) are correct. 

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About this question

This is a previous-year question from JEE Main 2022, covering the p Block Elements (Group 13 & 14) chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.