JEE Main 2020 — Ionic Equilibrium Question with Solution
From: JEE Main 2020 (Online) 9th January Evening Slot
Question
The solubility product of Cr(OH)3 at 298 K is
6.0 × 10–31. The concentration of hydroxide ions
in a saturated solution of Cr(OH)3 will be :
Choose an option
Show full solutionCorrect option: C
Correct answer
C(18 × 10–31)1/4
Step-by-step explanation
| Cr(OH)3 | ⇌ | Cr+3 | + | 3OH- |
|---|---|---|---|---|
| S | 3S |
Ksp = [Cr3+] [OH– ]3
6 × 10–31 = S × (3S)3
6 × 10–31 = 27 S4
S =
As [OH–] = 3S
=
= (18 × 10–31)1/4 M
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