JEE Main 2020 — Ionic Equilibrium Question with Solution
From: JEE Main 2020 (Online) 6th September Evening Slot
Question
If the solubility product of AB2 is 3.20 10–11 M3,
then the solubility of AB2 in pure water is
_____ 10–4 mol L–1.
[Assuming that neither kind of ion reacts with water]
[Assuming that neither kind of ion reacts with water]
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Show full solutionCorrect answer: 2
Correct answer
2
Step-by-step explanation
| AB2 | ⇌ | A2+(aq) | + | 2B-(aq) |
|---|---|---|---|---|
| s | 2s |
Ksp = 4s3 = 3.2 × 10–11
s3 = 8 × 10–12
s = 2 × 10–4
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