JEE Main 2020 — Ionic Equilibrium Question with Solution
From: JEE Main 2020 (Online) 9th January Morning Slot
Question
The Ksp for the following dissociation is
1.6 × 10–5
Which of the following choices is correct for a mixture of 300 mL 0.134 M Pb(NO3)2 and 100 mL 0.4 M NaCl ?
Which of the following choices is correct for a mixture of 300 mL 0.134 M Pb(NO3)2 and 100 mL 0.4 M NaCl ?
Choose an option
Show full solutionCorrect option: A
Correct answer
AQ > Ksp
Step-by-step explanation
[Pb2+] =
= 1.005 × 10–1 M
[Cl-] =
= 10–1 M
Q = [Pb2+] × [Cl–]2
= 0.1005 × (0.1)2
= 1.005 × 10–3
Given Ksp = 1.6 × 10–5
Q > Ksp
= 1.005 × 10–1 M
[Cl-] =
= 10–1 M
Q = [Pb2+] × [Cl–]2
= 0.1005 × (0.1)2
= 1.005 × 10–3
Given Ksp = 1.6 × 10–5
Q > Ksp
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