JEE Main 2022ChemistryIonic EquilibriumHardMCQ

JEE Main 2022 — Ionic Equilibrium Question with Solution

JEE Main 2022 (28 Jun Shift 2)

Question

A student needs to prepare a buffer solution of propanoic acid and its sodium salt with pH4. The ratio of CH3CH2COO-CH3CH2COOH required to make buffer is Given : KaCH3CH2COOH=1.3×10-5

Choose an option

Show full solutionCorrect option: B
Correct answer
B0.13

Step-by-step explanation

 Henderson's equation for calculating pH of acidic buffer solutions is given as

pH=pKa+logSaltAcid

pH=pKa+logCH3COO-CH3COOH

4=5-log(1.3)+logCH3COO-CH3COOH

log1.3×10-1=logCH3COO-CH3COOH

CH3COO-CH3COOH=0.13

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About this question

This is a previous-year question from JEE Main 2022, covering the Ionic Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.