JEE Main 2020ChemistryIonic EquilibriumEasyNumerical

JEE Main 2020 — Ionic Equilibrium Question with Solution

JEE Main 2020 (06 Sep Shift 2)

Question

If the solubility product of AB2 is 3.20×10-11 M3, then the solubility of AB2 in pure water is _______ ×10-4 mol L-1

[Assuming that neither kind of ion reacts with water]

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Show full solutionCorrect answer: 2
Correct answer
2

Step-by-step explanation

AB2⇌A2++2B−s2s

Ksp=4s3=3.20×10−11

So solubility =2×10−4 mol L−1

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About this question

This is a previous-year question from JEE Main 2020, covering the Ionic Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.