JEE Main 2022ChemistryIonic EquilibriumMediumMCQ

JEE Main 2022 — Ionic Equilibrium Question with Solution

JEE Main 2022 (25 Jun Shift 2)

Question

The Ksp for bismuth sulphide Bi2S3 is 1.08×10-73. The solubility of Bi2S3 in molL-1 at 298 K is

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Show full solutionCorrect option: A
Correct answer
A1.0×10-15

Step-by-step explanation

Bi2S3 will get dissociated as:

Bi2S3⇌2Bi+3+3S-2              2s         3s

Here,

 Ksp=2s23s3=108 s5s=Ksp10815s=1.08×10-7310815s=10-15 mol L-1

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About this question

This is a previous-year question from JEE Main 2022, covering the Ionic Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.