JEE Main 2021ChemistryIonic EquilibriumMediumNumerical

JEE Main 2021 — Ionic Equilibrium Question with Solution

JEE Main 2021 (31 Aug Shift 1)

Question

A3B2 is a sparingly soluble salt of molar mass Mg mol-1 and solubility x g L-1. The solubility product satisfies Ksp=axM5. The value of a is __________ . (Integer answer)

Enter your answer

Show full solutionCorrect answer: 108
Correct answer
108

Step-by-step explanation

Solubility =xm mole/lit
A3B2s⇌3A2+3xM(aqs)+2B3-(aqs)2xM
Ksp=3xM32xM2
=3322xm5
=27×4xm5
=108xm5=axM5
So a=108

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Ionic Equilibrium chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2021, covering the Ionic Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.