JEE Main 2021ChemistryIonic EquilibriumPh Buffer And IndicatorsmediumNumerical

JEE Main 2021Ionic Equilibrium Question with Solution

From: JEE Main 2021 (Online) 31st August Evening Shift

Question

The pH of a solution obtained by mixing 50 mL of 1 M HCl and 30 mL of 1 M NaOH is x 104. The value of x is ____________. (Nearest integer) [log 2.5 = 0.3979]

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Show full solutionCorrect answer: 6021
Correct answer
6021

Step-by-step explanation

JEE Main 2021 (Online) 31st August Evening Shift Chemistry - Ionic Equilibrium Question 59 English Explanation



pH = log 2.15 10-1 = 1 0.3979 = 0.6021

pH = 6021 10-4

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About this question

This is a previous-year question from JEE Main 2021, covering the Ionic Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.