JEE Main 2019ChemistryIonic EquilibriumMediumMCQ

JEE Main 2019 — Ionic Equilibrium Question with Solution

JEE Main 2019 (12 Jan Shift 2)

Question

If Ksp of Ag2CO3 is 8×10-12 , the molar solubility of Ag2CO3 in 0.1 M AgNO3 is:

Choose an option

Show full solutionCorrect option: D
Correct answer
D8x10-10M

Step-by-step explanation

(i)

(ii) 

K sp =8× 10 −12 = ( 2 S ′ +0.1 ) 2 S ′

or S ′ =8× 10 −10 M

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About this question

This is a previous-year question from JEE Main 2019, covering the Ionic Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.